Calculo prolixiori prodit: . 2 5
8. 150= 3190 49,,77 et t.= 21
*. 150= 2300 28,41.. t.= 157 21,89 8. 150= 1360 51,80. 5.= 104 27,455
quo valores? ne singula quidem temporis minuta prima mutantur.
§ 35.
His valoribus in aechuatione mm.*.. 800 145,963 †. 0,18160 sin(t. 150+† 1770 17,6)+ 025318 sin(t. 150 †. 1550 6,2) Positis, sequitur:
. Imm minimum,= 15* 21 89= 3* 21 s9 matutina et B00= 745,852 maximum,= 214 19˙32= 9 19 ,32 antemerid. et 800= 746,331 minimum,,= 4 10,50= 4 10,50 pomerid. et B0)=—= 745,557 maximum,,= 105 27,45= 10* 27 45 vespertin. et B)= 746,123, Est igitur 3 .... 2... 2. mm 2 5* 1 1) differentia inter maximum majus et minimum minus= 0,774 aestus totalis, fluctuatio man variatio diurna; ; 3.. 4. mm... 2) differentia inter maximum minus et minimum majus= 0,271, fluctuatio minor, variatio Doctunn,
ita ut variatio diurna nocturnam ter fere superet;. . IIm 3) differentia inter maximum majus(diurnum) et maximum minus(nocturnum)= 0,208;
.. umm 4) differentia inter minimum majus(nocturnum) et minimum minus(diurnum)= 0,295, igituy l. nima inter se magis differunt quam maxima.
§. 36.
Postremo si quaeritur tempus, quo atmosphaera statum medium obtineat sive medium barome- tricum intret, aequatio u' sin(t. 150+ ²)+ u“ sin(t. 300+†)= o, et nostris observationibus applican:
0,18160 sin(t. 150+ 1770 17,6)+ 0, 25318 sin(t. 300+ 1550 6,2)= 0 responsum nobis offert..
§. 37.
Posito t. 150=, ergot 300= 2z et adhibita formula ein(2+()= sin a cos b+† sin 5 cosa, ista Mutatdi i u(sin cos+ cos æ sin v)+ u¹(sin 2 x cos“+ cos 2 sin»)= 0. Est vero cos 2⸗= 2 cos a*—1 et sin 2= 2 sin æ cos æ, inde oritur: u¹(sin æ cos»+, cos æ sin 2-)+† u(2 sin æ cos x cos+ 2 cos xe sin v— sin w)= 0. Est autem sin== /(1— cos*r), inde sequitur: u[cos d N(1— cos**)+ cos z sin v+ u“[2 cos æ cos v' Nd— cos* † 2 cos e sin— Ssin 6= 0;3 Posito cos= g et uncinis solutis prodit: u“ cos v' N(1— 99 † u’ sin 2*.+ 2 u“ cos vé, g N(L 9)+ 2 u“ sin v“„e— u sin u= 03 et transpositione radicalium: (u“ cos v+† 2 u“ cos 5, 9) N(1— ge)= u sin“— u. ain vI, g— 2 2“ sin u“, ge;
19 ,32 r t. 150= 620 37,56.„ t.= A1 10,50— 44
inde quadratura sive reductione:
(ul cos+%ᷣ 2 un cos„ J)*(1— 9)=(u' sin p“— a“ sin 90. g— 2 u“ sin»“. J²)?; give- 2
„„. 2 2 · — 4 n2 cos» 2, g— 4 u, u“ cos e cos v. ps †.(A uss cos p“:— unr cos 5,2). 92+† 4 u u“ cos v' cos ². † u2 cos v. ₰
... 3.. 7.*. 91 92 J*. 4 2 2 sin v“2,* † 4 u' u“ gin v' sin v,—(4 u¹s sin a"*— w' zin»²) 22 bN— 2 u. u“ sin w sin u,„ † u gin 2.¹.


